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x^2+4=-3+2x
We move all terms to the left:
x^2+4-(-3+2x)=0
We add all the numbers together, and all the variables
x^2-(2x-3)+4=0
We get rid of parentheses
x^2-2x+3+4=0
We add all the numbers together, and all the variables
x^2-2x+7=0
a = 1; b = -2; c = +7;
Δ = b2-4ac
Δ = -22-4·1·7
Δ = -24
Delta is less than zero, so there is no solution for the equation
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